Question

Find the amount and compound interest on ₹ 1200 for 2yrs at 6% p.a ?

Answer 1

Answer:

Amount- 1348.32

C I- 148.32

Step-by-step explanation:

Amount = Principle(1+R/100)^n

where n is time

Amount = 1200(1+6/100)^2

= 1200(106/100)^2

Amount = 1348.32

Answer 2

Principal = ₹ 1200

Time = 2 years

Rate of interest = 6% p.a.

$Amount \\ = ₹1200(1 + \frac{6}{100})^{2} \\ = ₹1200 \times \frac{53}{50} \times \frac{53}{50} \\ = ₹1348.32$

$Compound \: \: interest \\ = ₹(1348.32 - 1200) \\ = ₹148.32$

Answers:

Amount = ₹1348.32

Compound interest = ₹148.32