Find the amount and compound interest on 12800 for one year at 15/2% p.a compounded semi-annually
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Answered by
10
principal=12,800
rate of interest =15/2%×2=15%
time =1=2half years
so, amount =12,800×(1+r/100)²
= 12800×(1+15/100)²
= 12800×105/100×105/100
= Rs14,112
C. I =14112-12800=Rs1312
rate of interest =15/2%×2=15%
time =1=2half years
so, amount =12,800×(1+r/100)²
= 12800×(1+15/100)²
= 12800×105/100×105/100
= Rs14,112
C. I =14112-12800=Rs1312
siddhartharao77:
I think its wrong bro
Answered by
6
Given Principal P = 12800,n = 2 and R = 15/2 Semi annually = 15/4%.
We know that A = P(1+r/100)^n
= 12800(1 + (15/4)/100)^2
= 12800((400 + 15)/100)^2
= 12800(415/100)^2
= 13778.
We know that CI = A - P
= 13778 - 12800
= 978 rupees.
Hope this helps!
We know that A = P(1+r/100)^n
= 12800(1 + (15/4)/100)^2
= 12800((400 + 15)/100)^2
= 12800(415/100)^2
= 13778.
We know that CI = A - P
= 13778 - 12800
= 978 rupees.
Hope this helps!
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