Math, asked by manesumedh52, 2 months ago


Find the amount and compound interest on 13500 for 2 years 6 months at 10% per
annum compounded annually.

Answers

Answered by Anonymous
122

Answer :-

Given :-

  • Principal = Rs. 13500
  • Time = 2 years 6 months = 2.5 years
  • Rate of interest = 10% p.a.

To Find :-

  • Compound interest
  • Amount

Solution :-

We know that,

\sf A = P \Big( 1 + \frac{R}{100}\Big)^n

Substituting the value in formula -

\implies\sf A = 13500 \Big( 1 + \frac{1\cancel0}{10\cancel0}\Big)^{2.5}

\implies\sf A =  13500 \Big( 1 + \frac{1}{10}\Big)^{2.5}

\implies\sf A = 13500 \Big(\frac{11}{10}\Big)^{2.5}

\implies\sf A = 13500 \times \Big(\frac{11}{10}\Big)^2 \times \Big(\frac{11}{10}\Big)^{0.5}

\implies\sf A \approx 135\cancel{00} \times \frac{121}{1\cancel{00}} \times 1

\implies\sf A = 16335

Amount = Rs. 16,335

We also know that,

Interest = Amount - Principal

Substituting the value -

Interest = 16335 - 13500

= 2,835

Compound interest = Rs. 2835

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