Question

Find the amount and compound interest on ₹18000 for 2 years at 10% per annum compounded annually.​

Answer 1

Given :

⬤ Principal = ₹ 18000 .

⬤ Time Taken = 2 years .

⬤ Rate of Interest = 10%

To Find :

⬤ Amount .

⬤ Compound Interest.

Formula Used :

$\bf[\:{A = P \bigg(1 + \dfrac{r}{100}\bigg)}^{2}\:]$

• A = Amount
• P = Principal
• R = Rate
• T = Time

Solution :

According to the Formula :-

$\bf{A = 18000\:\: \bigg(\dfrac{1}{1} + \dfrac{10}{100}\bigg)^{2}}$

$\sf{A = 18000\:\: \bigg(\dfrac{100+10}{100}\bigg)^{2}}$

$\sf{A = 18000\:\: \bigg( \dfrac{110}{100} \bigg)^{2}}$

$\sf{A = 18000\:\: \bigg( \dfrac{12100}{10000}\bigg)}$

$\sf{A = \dfrac{18000 \times{121}}{100}}$

$\sf{A = \dfrac{2178000}{100}}$

$\large\tt\underline{A = 21780}$

Therefore , Amount is ₹ 21780.

Formula Used :

$\bf[\:{C.I = A - P}\:]$

• C.I = Compound Interest
• A = Amount
• P = Principal

Now :

₹21780 - ₹18000

3780

Therefore , Compound Interest is ₹ 3780.

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \:Given:- }}}$

• Principal (P) = ₹ 18000 .
• Time (T) = 2 years
• Rate of Interest (R) = 10%

$\large\underline{ \underline{ \sf \maltese{ \:To \: find :- }}}$

• Amount (A)
• Compound Interest (CI)

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

According to the Formula :-

$\qquad \bull \: { \sf{A }= \bf P \bigg(1 + \dfrac{R}{100}\bigg)}^{2}$

$\qquad \quad {:} \longrightarrow \sf{\sf{A = 18000\:\: \bigg(1 + \dfrac{10}{100}\bigg)^{2}}}$

$\qquad \quad {:} \longrightarrow \sf{\sf{A = 18000\:\: \bigg(\dfrac{100+10}{100}\bigg)^{2}}}$

$\qquad \quad {:} \longrightarrow \sf{\sf{A = 18000\:\: \bigg(\dfrac{11 \cancel0}{10 \cancel0}\bigg)^{2}}}$

$\qquad \quad {:} \longrightarrow \sf{\sf{A = 180 \cancel0 \cancel0 \times \dfrac{121}{1 \cancel0 \cancel0}}}$

$\qquad \quad {:} \longrightarrow \underline {\boxed{\sf{A =21780 }}}$

$\qquad \therefore\: \sf{ Amount = \underline {\underline{₹ \: 21780} }}$

According to the formula:–

$\qquad\bull \: {\sf\:{CI = \bf A - P}}$

$\qquad\quad{:}\longrightarrow\sf{21780 - 18000}$

$\qquad\quad {:} \longrightarrow \underline {\boxed{\sf{A =3780 }}}$

$\qquad \therefore\: \sf{ Compound \: Interest = \underline {\underline{₹ 3780 }}}$