Question

find the amount and compound interest on ₹20000 at 7.5 per annum after 3 years​

Answer 1

Answer:

Step-by-step explanation:

Here, P= Rs. 8000,R=10% per annum and n=3 years

Using the formula, A=P(1+  

100

R

​

)  

n

 

Amount after 3 years =8000×(1+  

100

10

​

)  

3

 

=8000×  

10

11

​

×  

10

11

​

×  

10

11

​

 

=10648

Thus, amount after 3 years = Rs. 1648.

Answer 2

Given :

• Principal = Rs.20000
• Rate = 7.5 %
• Time = 3 years

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To Find :

• Amount = ?
• Compound Interest = ?

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Solution :

~ Formula Used :

• ${\underline{\boxed{\red{\sf{ A = P \bigg( 1 + \dfrac{R}{100} \bigg)^n }}}}}$

• ${\underline{\boxed{\red{\sf{ C.I = Amount - Principal }}}}}$

Where :

• ➬ A = Amount
• ➬ C.I = Compound Interest
• ➬ P = Principal
• ➬ R = Rate
• ➬ n = Time

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~ Calculating the Amount :

${\dashrightarrow{\qquad{\sf{ A = P \bigg( 1 + \dfrac{R}{100} \bigg)^n }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ A = 20000 \bigg( 1 + \dfrac{7.5}{100} \bigg)^3 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ A = 20000 \bigg( 1 + \dfrac{75}{1000} \bigg)^3 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ A = 20000 \bigg( 1 + \cancel\dfrac{75}{1000} \bigg)^3 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ A = 20000 \bigg( 1 + 0.075 \bigg)^3 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ A = 20000 \bigg( 1.075 \bigg)^3 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ A = 20000 \times 1.075 \times 1.075 \times 1.075 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ A = 20000 \times 1.242296875 }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pmb{\color{darkblue}{\frak{ Amount = ₹ \; 24845.93 }}}}}}}}$

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~ Calculating the Compound Interest :

${\longmapsto{\qquad{\sf{ Compound \; Intrest = Amount - Principal }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Compound \; Intrest = 24845.93 - 20000 }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pmb{\pink{\frak{ Compound \; Interest = ₹ \; 4845.93 }}}}}}}}$

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~ Therefore :

❛❛ Compound Interest on this sum of money is ₹ 4845.93 . ❜❜

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