. Find the amount and compound interest
on 24,000 compounded half yearly for
1.5 years at the rate of 10% per annum
Answers
Answered by
1
Answer:
Interest compounded half yearly
⟹r=(10%)/2=5% per interest period.
No.of interest period (n)=2(3/2)=3
P=Rs.2400
CI=P[(1+
100
r
)
n
−1]
CI=24000[(1+
100
10
)
3
−1]=3783
Hence, the compound interest=Rs.3,783
Step-by-step explanation:
hope it's helpful
Answered by
1
Answer:
Amount = Rs 27783 and CI= 3783
Step-by-step explanation:
Amount = 24000(1+10/200)^3
=27783
So, CI = 27783 - 24000
= 3783
Similar questions
⟹r=(10%)/2=5% per interest period.
No.of interest period (n)=2(3/2)=3
P=Rs.2400
CI=P[(1+
100
r
)
n
−1]
CI=24000[(1+
100
10
)
3
−1]=3783
Hence, the compound interest=Rs.3,783