Math, asked by vijaykrishna43, 1 month ago

. Find the amount and compound interest
on 24,000 compounded half yearly for
1.5 years at the rate of 10% per annum​


meenakumari666666: Interest compounded half yearly
⟹r=(10%)/2=5% per interest period.
No.of interest period (n)=2(3/2)=3
P=Rs.2400
CI=P[(1+
100
r

)
n
−1]
CI=24000[(1+
100
10

)
3
−1]=3783
Hence, the compound interest=Rs.3,783

Answers

Answered by hardikthakur301
1

Answer:

Interest compounded half yearly

⟹r=(10%)/2=5% per interest period.

No.of interest period (n)=2(3/2)=3

P=Rs.2400

CI=P[(1+

100

r

)

n

−1]

CI=24000[(1+

100

10

)

3

−1]=3783

Hence, the compound interest=Rs.3,783

Step-by-step explanation:

hope it's helpful

Answered by joydebsarkar28619
1

Answer:

Amount = Rs 27783 and CI= 3783

Step-by-step explanation:

Amount = 24000(1+10/200)^3

=27783

So, CI = 27783 - 24000

          = 3783

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