Question

find the amount and compound interest on 2500 for 3years at 4percent p.a compounded annually

Answer 1

A=p×(1+r/100)^n
A=2500×(1+4/100)^3
A=2812.16

CI=A_ P
2812.16_ 2500
=312.16

Answer 2

P=2500
N=3Yrs
R=4%
A =P(1+(R)/100) ^ N
C.I.=A - P

A=2500(1+(4)/100)^3
=2500(104/100)^3
=2500 x (104 x 104 x 104)/(100 x 100 x 100)
=(13 x 52 x 104)/25
=(676 x 104)/25
=70304/25
=2812.16

C.I.=2812.16 - 2500
C.I.=312.16