find the amount and compound interest on ₹25000 for 3 years at 4% p.a. compounded annually.
Answers
Answered by
87
Hi ,
It is given that ,
Principal = p = Rs 25000
Time = t = 3 years
Rate of interest per annum = r = 4%
Number of times interest paid (n ) = 3
Amount ( A ) = p ( 1 + r/100 )ⁿ
A = 25000 ( 1 + 4/100 )³
A = 25000 ( 1 + 1/25 )³
A = 25000 ( 26/25 )³
A = (25000×26×26×26)/( 25×25×25)
A = Rs 28121.60
Therefore ,
Compound interest = A - p
C.I = 28121.60 - 25000
C.I = Rs 3121.60
I hope this helps you.
: )
It is given that ,
Principal = p = Rs 25000
Time = t = 3 years
Rate of interest per annum = r = 4%
Number of times interest paid (n ) = 3
Amount ( A ) = p ( 1 + r/100 )ⁿ
A = 25000 ( 1 + 4/100 )³
A = 25000 ( 1 + 1/25 )³
A = 25000 ( 26/25 )³
A = (25000×26×26×26)/( 25×25×25)
A = Rs 28121.60
Therefore ,
Compound interest = A - p
C.I = 28121.60 - 25000
C.I = Rs 3121.60
I hope this helps you.
: )
Answered by
37
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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