find the amount and compound interest on ₹25000 for 3 years at 9 %p.a. compounded annually.
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A=P(1+r/100)^n (where p denotes principal, A is amount, r is ratio and n is time)
25000(1+9/100)^3
25000(109×109×109)÷1000000
32375.725
Amount = 32375.725
CI (A - P)= 7375.725
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