Question

Find the amount and compound interest on a sum ₹15625 at 4% per annum for 2 years compound annually​

Answer 1

Answer:

Given :-

• A sum of Rs 15625 at 4% per annum for 2 years.

To Find :-

• What is the amount and compound interest.

Solution :-

First, we have to find the amount :

Given :

• Principal = Rs 15625
• Rate of Interest = 4% per annum
• Time Period = 2 years

According to the question by using the formula we get,

$\implies \sf\boxed{\bold{\pink{A =\: P\bigg(1 + \dfrac{r}{100}\bigg)^n}}}$

$\implies \sf A =\: 15625\bigg(1 + \dfrac{4}{100}\bigg)^2$

$\implies \sf A =\: 15625\bigg(\dfrac{104}{100}\bigg)^2$

$\implies \sf A =\: 15625 \times \dfrac{104}{100} \times \dfrac{104}{100}$

$\implies \sf A =\: \dfrac{169000000}{10000}$

$\implies \sf\bold{\purple{A =\: Rs\: 16900}}$

Now, we have to find the compound interest :-

Given :

• Amount = Rs 16900
• Principal = Rs 15625

According to the question by using the formula we get,

$\footnotesize \implies \sf\boxed{\bold{\pink{Compound\: Interest =\: A - P}}}$

$\implies \sf Compound\: Interest =\: Rs\: 16900 - Rs\: 15625$

$\implies \sf\bold{\red{Compound\: Interest =\: Rs\: 1275}}$

$\therefore$ The amount is Rs 16900 and the compound interest is Rs 1275 .

Answer 2

Question :-

• Find the Amount and Compound Interest on a sum Rs. 15,625 at 4 % per annum for 2 years compound annually .

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Answer :-

• Amount = Rs. 16900
• Compound Interest = Rs. 1275

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Explanation :-

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∓ Here, Principal is given Rs. 15,625 . Rate of Interest is given 4 % per annum . Time Period is given 2 years . And, we have to calculate the Amount and Compound Interest .

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• Now, let's solve step by step -----

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◆ Formula Required :-

• $\sf{Amount = Principal \times \bigg(1 + \frac{Rate}{100} \bigg) {}^{Time} }$

• $\sf{Compound \: Interest = Amount - Principal}$

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● First, we will find the Amount :-

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$\dashrightarrow \: \sf{Amount = P \times \bigg(1 + \frac{r}{100} \bigg) {}^{n} } \\ \\ \dashrightarrow \: \sf{Amount = 15625 \times \bigg(1 + \frac{4}{100} \bigg) {}^{2} } \\ \\ \dashrightarrow \: \sf{Amount =15625 \times \bigg( \frac{104}{100} \bigg) {}^{2} } \\ \\ \dashrightarrow \: \sf{Amount =15625 \times \bigg( \frac{10816}{10000} \bigg) } \\ \\ \dashrightarrow \: \sf{Amount = \frac{169000000}{10000} } \\ \\ \dashrightarrow \: \sf{Amount = Rs. \: 16900}$

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● Now, let's find Compound Interest :-

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$\dashrightarrow \: \sf{Compound \: Interest = A - P} \\ \\ \dashrightarrow \: \sf{Compound \: Interest = 16900 - 15625} \\ \\ \dashrightarrow \: \sf{Compound \: Interest =Rs. \: 1275 }$

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Hence :-

• Amount = Rs. 16900
• Compound Interest = Rs. 1275

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