Find the amount and compound interest on a sum of 15,000 at 6% per annum for 3 years compounded
annually.
Answers
Answered by
3
Principal = Rs 15000
First year:
Principal = Rs 15000
Interest = 8%
Amount = 15000 + (0.08 x 15000) = Rs 16200
Second year:
Principal = Rs 16200
Interest = 10%
Amount = 16200 + (0.1 x 16200) = Rs 17820
Third year:
Principal = Rs 15000
Interest = 12%
Amount = 17820 + (0.12 x 17820) = Rs 19958.40
Interest = 19958.4 - 15000 = Rs 4958.40
Answer: Amount = Rs 19958.40 and Interest = Rs 4958.40
Answered by
2
Answer:
Simple Interest
I=
1 0 0
P N R
Here for first year,
P=
Rs.15,000
N=
1
year
R=
6
%
So, Interest at the end of 1st year
I=
100
15,000×1×6
=
Rs.900
And for second year,
P=
Rs.15,000+
Rs.900=
Rs.15,900
N=
1
year
R=
8%
I=
100
15,900×1×8
=
Rs.1272
And, for third year,
P=
Rs.15,900+
Rs.1,272=
Rs.17,172
N=
1
year
R=
10%
I=
100
17,172×1×10
=
Rs.1,717.2
So, total interest
=
Rs.900+
Rs.1,272+
Rs.1,717.2=
Rs.3,889.20
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