Question

Find the amount and compound interest on Rs.3000 at 10% p.a for 3 years *​

Answer 1

Answer:

Principal (P) = Rs.3000

Rate (R) = 10% p.a.

Time (T) = 3 years

Amount (A) = P × (1 + R/100)ⁿ

=> A = 3000 × (1 + 10/100)³

=> A = 3000 × (11/10)³

=> A = 3000 × 11/10 × 11/10 × 11/10

=> A = Rs.3993

Compound Interest = Rs.(3993-3000) = Rs.993

Answer 2

Answer:

3993

Step-by-step explanation:

$a =p { (1 + \frac{r}{100}) }^{n} \\ = 3000( \frac{110}{100} )^{3} \\ = 3000 \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100} \\ = 3 \times 11 \times 11 \times 11 \\ = 3 \times 1331 \\ = 3993$