find the amount and compound interest on Rs 4000 for 3 years at 5% per annum
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a=p(1+r/100)^n
a=4000(1+5/100)^3
a=4000(21/20)^3
a=4000×21/20×21/20×21/20
a=21*21*21/2
a=4630.50
ci=A-P
ci=4630.50-4000
ci=630.50
a=4000(1+5/100)^3
a=4000(21/20)^3
a=4000×21/20×21/20×21/20
a=21*21*21/2
a=4630.50
ci=A-P
ci=4630.50-4000
ci=630.50
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