Find the amount and compound interest on rupees 100000 compounded quarterly for 9 months at the rate of 4% per annum
Answers
Answered by
14
P =100000
n ( time period) = 9 months
R = 4%
compounded quarterly
☆ A = P (1+ R/4×100)^4n
A = 100000 (1+4/4×100)^4×(9/12)
= 100000 (1+4/400)^3
= 100000 (404/400)^3
=100000 (1.03)
= 103000
amount = Rs. 103000
☆ compound interest = A _P
103000 _ 100000
=Rs. 3000
amount = Rs.103000
c.i = Rs. 3000
n ( time period) = 9 months
R = 4%
compounded quarterly
☆ A = P (1+ R/4×100)^4n
A = 100000 (1+4/4×100)^4×(9/12)
= 100000 (1+4/400)^3
= 100000 (404/400)^3
=100000 (1.03)
= 103000
amount = Rs. 103000
☆ compound interest = A _P
103000 _ 100000
=Rs. 3000
amount = Rs.103000
c.i = Rs. 3000
Answered by
11
Answer:
Step-by-step explanation:
Attachments:
Similar questions