Question

find the amount and compound interest on rupees 12000 in 1 year at 10% per annum compounded halfyear

Answer 1

Answer:

Principal (P) = ₹ 12,000

Rate (r) = 10%

Time (t) = 1 years

Amount = P × (1 +(r/ (2 × 100)) n × 2

= ₹ 12,000 × (1 + (10/200)) 2

= ₹ 12,000 × (210/200)2

= ₹12,000 × 21/20 × 21/20 = ₹ 13,230

C.I. = Amount – Principal

= ₹ 13230 - ₹ 12000 = ₹1230

Answer 2

Answer:

formula of compound interest when the interest is compounded half yearly

A=p(1+R/2×100)²ⁿ

Step-by-step explanation:

A=12000×(1+10/2×100)²

A=12000×(21/20)²

A=12000×21/20×21/20

A=13230

C.I.=A-P=13230-12000=1230