find the amount and compound interest on rupees 12000 in 2 year at 10 % per annum
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Answer:
Here P=12,000 Rs., n=2 years, R=10
Amount(A)=P(1+100R)n
=12000(1+10010)2
=12000(1011)2
=10012000×121
=14,520 Rs.
Compound interest(C.I)=A−P=14,520−12,000=2520
Hence, the compound interest is Rs. 2,520
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