Math, asked by kamritanshu965, 7 months ago

find the amount and compound interest on rupees 15000 for 3 years the rate of interest being 8% for the first year 9% for the second year and 10% for the third year

Answers

Answered by rjaniruthan1981
7

Answer:

Simple Interest I=

100

PNR

Here for first year,

P=Rs.15,000

N=1 year

R=6 %

So, Interest at the end of 1st year I=

100

15,000×1×6

=Rs.900

And for second year,

P=Rs.15,000+Rs.900=Rs.15,900

N=1 year

R=8%

I=

100

15,900×1×8

=Rs.1272

And, for third year,

P=Rs.15,900+Rs.1,272=Rs.17,172

N=1 year

R=10%

I=

100

17,172×1×10

=Rs.1,717.2

So, total interest =Rs.900+Rs.1,272+Rs.1,717.2=Rs.3,889.20

Answered by samirasingh13
5

Step-by-step explanation:

simple interest =Pnr/100

here for first year,

P=15,000 rs

N=1year

R=6%

so, interest at the end of first year=15000*1*6/100=900

and for second year

P=15,000+900=15900

N=1yr

R=8%

I=15,900*1*8/100=1272

and for third year

P=15,900+1272=17172

N=1yr

R=10%

I=17172*1*10/100=1712.2

so total interest=900+1272+1717.2=3,889.20

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