find the amount and compound interest on rupees 15000 for 3 years the rate of interest being 8% for the first year 9% for the second year and 10% for the third year
Answers
Answered by
7
Answer:
Simple Interest I=
100
PNR
Here for first year,
P=Rs.15,000
N=1 year
R=6 %
So, Interest at the end of 1st year I=
100
15,000×1×6
=Rs.900
And for second year,
P=Rs.15,000+Rs.900=Rs.15,900
N=1 year
R=8%
I=
100
15,900×1×8
=Rs.1272
And, for third year,
P=Rs.15,900+Rs.1,272=Rs.17,172
N=1 year
R=10%
I=
100
17,172×1×10
=Rs.1,717.2
So, total interest =Rs.900+Rs.1,272+Rs.1,717.2=Rs.3,889.20
Answered by
5
Step-by-step explanation:
simple interest =Pnr/100
here for first year,
P=15,000 rs
N=1year
R=6%
so, interest at the end of first year=15000*1*6/100=900
and for second year
P=15,000+900=15900
N=1yr
R=8%
I=15,900*1*8/100=1272
and for third year
P=15,900+1272=17172
N=1yr
R=10%
I=17172*1*10/100=1712.2
so total interest=900+1272+1717.2=3,889.20
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