Question

Find the amount and compound interest:-

Rs. 6000 for 3 years at 6% p.a .

Answer 1

Question :

Find the amount and compound interest:-Rs. 6000 for 3 years at 6% p.a .

Given Data :

Principal(p) → ₹6000

Rate(r) → 6% per annum compounded annually

Time(n) → 3years

Amount(a) → ?

To find :

amount and compound Interest

Formula Used :

$\sf \small a = p(1 + \frac{r}{100} )^{n}$

C.I. = Amount – Principal

Solution :

First we have to find the amount and then we need to get the Interest.

$\sf \small a = p(1 + \frac{r}{100} )^{n}$

$\sf \small a = 6000 {(1 + \frac{6}{100} )}^{3}$

$\sf \small a = 6000 {( \frac{53}{50} )}^{3}$

$\sf \small a = 6000 \times \frac{148877}{125000}$

$\sf \small a = \frac{893262}{125}$

$\sf \small \: a = 7416.09$

Now we got the amount we need to find the Compound Interest(C.I.)

C.I. = Amount – Principal

C.I. = ₹7146.09 – ₹6000

C.I. = ₹ 146.09

• So the compound Interest is ₹146.09 and the amount is ₹ 7146.09

Answer 2

Question :

Find the amount and compound interest:-Rs. 6000 for 3 years at 6% p.a .

Given Data :

Principal(p) → ₹6000

Rate(r) → 6% per annum compounded annually

Time(n) → 3years

Amount(a) → ?

To find :

amount and compound Interest

Formula Used :

$\sf \small a = p(1 + \frac{r}{100} )^{n}$

C.I. = Amount – Principal

Solution :

First we have to find the amount and then we need to get the Interest.

$\sf \small a = p(1 + \frac{r}{100} )^{n}$

$\sf \small a = 6000 {(1 + \frac{6}{100} )}^{3}$

$\sf \small a = 6000 {( \frac{53}{50} )}^{3}$

$\sf \small a = 6000 \times \frac{148877}{125000}$

$\sf \small a = \frac{893262}{125}$

$\sf \small \: a = 7416.09$

Now we got the amount we need to find the Compound Interest(C.I.)

C.I. = Amount – Principal

C.I. = ₹7146.09 – ₹6000

C.I. = ₹ 146.09

So the compound Interest is ₹146.09 and the amount is ₹ 7146.09

"Hope this will help you"