find the amount and compound interestof rupees 25000 for 3 years at the rate of 4percent per annum compounded annually
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Answer:
Step-by-step explanation:
A=P[1+ 100 r ] n
⇒ A=Rs.25,000×( 100 106 ) 3
⇒ 25,000× 50 53 × 50 53 × 50 53
⇒ A=Rs.29,775.40
⇒ CI=A−P
⇒ Rs.29,775.40−Rs.25,000
∴ Compound Interest=Rs.4775.40.
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