find the amount and compound intrest on ₹4000 at 12% for 2 years
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Answer:
C.I =P[1+r/100]n
C.I= 4000[1+12/100] ×2
4000[112/100]×2=4000×112/100×112/100
=5017.60
C.I=Amount - Principal
=5017.60-4000
=Rs 1017.60
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