Find the amount and compounded interest on rupees 15,000 for 3 years,the rate of interest being 8% for the first year,9% for the second year and 10% for the third year.
Answers
Answer:
SimpleInterest I=
100
PNR
Here for first year,
Here for first year, P=Rs.15,000
Here for first year, P=Rs.15,000N=1 year
Here for first year, P=Rs.15,000N=1 yearR=6 %
Here for first year, P=Rs.15,000N=1 yearR=6 % So, Interest at the end of 1st year I=
\frac{15,000 \times 1 \times 6}{100} = \: Rs.900 < /strong > < /p > < p > < /p > < p > < strong > [tex] \frac{15,000 \times 1 \times 6}{100} = \: Rs.900
100
15,000×1×6
=Rs.900</strong></p><p></p><p><strong>[tex]
100
15,000×1×6
=Rs.900
And for second year,
And for second year, P=Rs.15,000+Rs.900=Rs.15,900
And for second year, P=Rs.15,000+Rs.900=Rs.15,900N=1 year
And for second year, P=Rs.15,000+Rs.900=Rs.15,900N=1 yearR=8%
I= \: \frac{15,900×1×8}{100} = Rs.1272 < /strong > < /p > < p > < /p > < p > < strong > [tex]I= \: \frac{15,900×1×8}{100} = Rs.1272I=
100
15,900×1×8
=Rs.1272</strong></p><p></p><p><strong>[tex]I=
100
15,900×1×8
=Rs.1272
And, for third year,
And, for third year, P=Rs.15,900+Rs.1,272=Rs.17,172
And, for third year, P=Rs.15,900+Rs.1,272=Rs.17,172N=1 year
And, for third year, P=Rs.15,900+Rs.1,272=Rs.17,172N=1 year R=10%
I= \: \frac{17,172×1×10}{100} = Rs.1,717.2 < /strong > < /p > < p > < /p > < p > < strong > [tex]I= \: \frac{17,172×1×10}{100} = Rs.1,717.2I=
100
17,172×1×10
=Rs.1,717.2</strong></p><p></p><p><strong>[tex]I=
100
17,172×1×10
=Rs.1,717.2
So, total interest =Rs.900+Rs.1,272+Rs.1,717.2=Rs.
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