Math, asked by chittechandrakala262, 1 month ago

Find the amount and interest of $5000 kept for 2 years at 7percent rate of interest

Answers

Answered by KB8
2

Step-by-step explanation:

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Given :

Principal = $ 5000

Rate of Interest = 7% per annum

Time = 2 years

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To find :

Interest and Amount after 2 years.

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According to question,

Simple Interest = \frac{PRT}{100} (∴ Here P = principal ,R = Rate of Interest ,T = Time.)

Simple Interest = 5000 x 7 x 2 / 100

Simple Interest = $ 700

∴Amount = Principal + Interest

 Amount = $ 5000 + $ 700

 Amount = $ 5700

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⇒ Here, the INTEREST is $700.

   And the AMOUNT is $ 5700.

Answered by Anonymous
79

Answer:

\large\underline{\underline{\bigstar{\textbf{\textsf{\: Given\::-}}}}}

  • ➽ Principle = $5000
  • ➽ Time = 2 years
  • ➽ Rate of Interest = 7%

\begin{gathered}\end{gathered}

\large\underline{\underline{\bigstar{\textbf{\textsf{\: To Find\::-}}}}}

  • ➽ Interest
  • ➽ Amount

\begin{gathered}\end{gathered}

\large\underline{\underline{\bigstar{\textbf{\textsf{\: Using Formulae\::-}}}}}

\quad\dag{\underline{\boxed{\sf{S.I =  \dfrac{P \times R \times T}{100}}}}}

\quad\dag{\underline{\boxed{\sf{A = P +  I}}}}

Where

  • ➽ S.I = Simple Interest
  • ➽ P = Principle
  • ➽ R = Rate
  • ➽ T = Time
  • ➽ A = Amount

\begin{gathered}\end{gathered}

\large\underline{\underline{\bigstar{\textbf{\textsf{\: Solution\::-}}}}}

\dag{\underline{\underline{\pmb{\frak{\red{Calculating \:  the \:  Simple Interest ...}}}}}}

\quad{\longmapsto{\sf{S.I =  \dfrac{P \times R \times T}{100}}}}

  • Substuting the values

\quad{\longmapsto{\sf{S.I =  \dfrac{5000 \times 7 \times 2}{100}}}}

\quad{\longmapsto{\sf{S.I =\dfrac{70000}{100}}}}

\quad{\longmapsto{\sf{S.I = \cancel\dfrac{70000}{100}}}}

\quad{\longmapsto{\sf{S.I ={\$700}}}}

\quad\bigstar{\underline{\boxed{\pmb{\sf{\purple{S.I ={\$700}}}}}}}

The Simple Interest is $700.

\begin{gathered}\end{gathered}

\dag{\underline{\underline{\pmb{\frak{\red{Now,Calculating \:  the \:  Amount...}}}}}}

\quad{ : \implies{\sf{A = P +  I}}}

  • Substuting the values

\quad{ : \implies{\sf{A = 5000 + 700}}}

\quad{ : \implies{\sf{A = \$5700}}}

\quad{\bigstar{\underline{\boxed{\pmb{\sf{\purple{A = \$5700}}}}}}}

The Amount is Rs $5700.

\begin{gathered}\end{gathered}

\large\underline{\underline{\bigstar{\textbf{\textsf{\: Learn More\::-}}}}}

\quad\dag{\underline{\boxed{\sf{\red{A ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}

\quad\dag{\underline{\boxed{\sf{\red{Amount = Principle + Interest}}}}}

\quad\dag{\underline{\boxed{\sf{\red{ P=Amount - Interest }}}}}

\quad\dag{\underline{\boxed{\sf{\red{ S.I = \dfrac{P \times R \times T}{100}}}}}}

\quad\dag{\underline{\boxed{\sf{\red{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}}}}}}

\quad\dag{\underline{\boxed{\sf{\red{P = \dfrac{Interest \times 100 }{Time \times Rate}}}}}}

\quad\dag{\underline{\boxed{\sf{\red{Rate =  \dfrac{Simple \:  Interest  \times 100}{Principle  \times Time}}}}}}

\quad\dag{\underline{\boxed{\sf{\red{ Time=  \dfrac{Simple \:  Interest  \times 100}{Principle  \times Rate}}}}}}

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