Question

Find the amount and interest of ₹ 5000 kept for 2 years at 7 % rate of interest.​

Answer 1

Step-by-step explanation:

$\huge{ \pink{ \underline{ \sf{Given: }}}}$

$\: \:$

• Principal : ₹ 5000
• Rate of Interest : 7%
• Time : 2 years

$\: \:$

$\huge{ \pink{ \underline{ \sf{To \: Find : }}}}$

$\: \:$

• The amount
• Interest

$\: \:$

$\huge{ \pink{ \underline{ \sf{ Solution: }}}}$

$\: \:$

$\displaystyle{ \sf{ \bf{Interest \: = \frac{P \times R \times T}{100} }}}$

$\: \:$

$\displaystyle{ \sf{Interest \: = \frac{5000 \times 7 \times 2}{100} }}$

$\displaystyle{ \sf{Interest \: = \frac{50 \cancel{00} \times 7 \times 2}{ \cancel{100}} }}$

$\displaystyle{ \sf{Interest \: = 50 \times 7 \times 2}}$

$\displaystyle{ \sf{Interest \: = \red{700}}}$

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$\: \:$

$\displaystyle{ \mathfrak{ \blue{Amount = Principal + Interest }}}$

$\mathfrak{ \purple{Amount = ₹5000 + ₹700}}$

$\mathfrak{ \pink{Amount =₹5700 }}$

$\: \:$

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Henceforth ,

$\displaystyle{ \bf{Amount = ₹ 5700}}$

$\displaystyle{ \bf{Interest = ₹700}}$

Know More :

$\quad\dag{\underline{\boxed{\sf{\red{ P=Amount - Interest }}}}}$

$\quad\dag{\underline{\boxed{\sf{\red{ S.I = \dfrac{P \times R \times T}{100}}}}}}$

$\quad\dag{\underline{\boxed{\sf{\red{P = \dfrac{Interest \times 100 }{Time \times Rate}}}}}}$

Answer 2

${\large{\bf{\red{\underline{\underline{Given :}}}}}}$

₹ 5000 kept for 2 years at 7 % rate of interest.

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${\large{\bf{\blue{\underline{\underline{To Find :}}}}}}$

Find the amount of interest .

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${\large{\bf{\orange{\underline{\underline{Solution :}}}}}}$

${\blue{\bigstar{\pink{\boxed{\mathfrak{Simple interest = \frac{p \times r \times t}{100} }}}}}}$

Here,

${\sf{\purple{P = Principle}}}$

${\sf{\purple{R = Rate}}}$

${\sf{\purple{T = Time}}}$

Than,

${\sf{\green{= \frac{P × R × T}{100} }}}$

${\sf{\green{= \frac{ 5000×7 × 2}{100} }}}$

${\sf{\green{= {\cancel \frac{ 5000×7 × 2}{100} }}}}$

${\blue{\underbrace{\bf{\red{\boxed{= 700}}}}}}$

So,

${\mathfrak{\green{The \: simple \: interest \: is \: Rs 700.}}}$

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${\underline{\large{\fcolorbox{red}{green}{XitzNobitaxX}}}}$