find the amount and the compound interest of 12000 rupees at 6% per annum compounded half yearly for 3/2 years
Answers
Answered by
1
Answer:
P=Rs.12,000
R=4% p.a
T=
2
3
=1
2
1
years
as compounded half yearly, n=3,r=2%
Amount=P(1+
100
r
)
n
=12000(1+
100
2
)
3
=12000(1+
50
1
)
3
=12000(
50
51
)
3
=12000×
125000
132651
∴Amount=Rs.12,734.49
C.I=A−P=12734.49−12000=Rs.734.49
Step-by-step explanation:
Answered by
3
Answer:
for 3 years, amount = 13911.29 interest = 1911.29
Step-by-step explanation:
a = 12000*(1+0.06/2)^3*2
a = 12000*1.15927
a = 13,911.29
Interest = 13911.29 - 12000 = 1911.29
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