Find the amount and the compound interest on ₹10000 for 3years at 12%per annum, compounded half yearly.
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0
Answer:
1000×112/100×112/100×112/100
Answered by
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Answer:
A=P[1+E/100]^n
P=10000
n=3 years
r=10%
A=P[1+E/100]^n
a=10000+[1+10/100]^3
=10000[1+1/10]^3
=10000[11/10]^3
=10000(1.1)(1.1)(1.1)
=13310
A-p
13310-10000
=3310
hope it might be correct
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