Question

Find the amount and the compound interest on 15,000 for 3 years at 10% per annum compounded annually
please give an appropriate step by step explaination.
The ans should be Rs 19965,Rs 4965 .​

Answer 1

Step-by-step explanation:

Principal- 15000

rate- 10%

time-3 years

amount= principal(1+rate/100)^time

A= 15000(1+10/100)^3

A=15000(100+10/100)^3

A=15000(110/100)^3

A=15000(11/10)^3

A=15000*1331/1000

A=15*1331

A=Rs.19965

Compound Interest- Amount-Prncipal= 19965-15000

                                                               = RS.4965

the loan will amount to Rs.19965

Answer 2

Solution :

$\underline{\bf{Given\::}}}}$

• Principal, (P) = Rs.15000
• Rate, (R) = 10%
• Time, (n) = 3 years.

$\underline{\bf{To\:find\::}}}}$

The amount & compound Interest of the compound annually.

$\underline{\bf{Explanation\::}}}}$

$\bigstar$Using formula of the compound annually :

$\boxed{\bf{Amount=Principal\bigg(1+\frac{R}{100} \bigg)^{n} }}}}$

A/q

$\longrightarrow\tt{A=15000\bigg(1+\dfrac{1\cancel{0}}{10\cancel{0}} \bigg)^{3} }\\\\\\\longrightarrow\tt{A=15000\bigg(1+\dfrac{1}{10} \bigg)^{3} }\\\\\\\longrightarrow\tt{A=15000\bigg(\dfrac{10+1}{10} \bigg)^{3} }\\\\\\\longrightarrow\tt{A=15000\bigg(\dfrac{11}{10} \bigg)^{3} }\\\\\\\longrightarrow\tt{A=15\cancel{000}\times \dfrac{11}{1\cancel{0}} \times \dfrac{11}{1\cancel{0}} \times \dfrac{11}{1\cancel{0}} }\\\\\longrightarrow\tt{A=Rs.(15\times 11\times 11\times 11)}$

$\longrightarrow\bf{A=Rs.19965}$

&

We know that compound Interest :

$\longrightarrow\sf{C.I.=Amount-Principal}\\\\\longrightarrow\sf{C.I.=Rs.19965-Rs.15000}\\\\\longrightarrow\bf{C.I.=Rs.4965}$