Math, asked by saurabhsingh988123, 3 months ago

Find the amount and the compound
interest on 15,000 for 3/2years
at 10% per annum the interest
being compounded half yourly​

Answers

Answered by adityanawale900
0

Step-by-step explanation:

The compound interest on rs 10000 in 2years at 4% per annum the interest being compounded half yearly is Rs.824.3216

Step-by-step explanation:

Principal = Rs.10000

Time = 2 years

Rate of interest = 4%

No. of compounds per year = 2

Formula : A = P(1+\frac{r}{n})^{nt}A=P(1+

n

r

)

nt

Where A is amount

P is principal

r = rate of interest

n = no. of compounds per year

Substitute the values in the formula :

A = 10000(1+\frac{0.04}{2})^{2 \times 2}

A = 10824.3216

Interest = Amount - Principal

Interest = 10824.3216-10000

Interest = 824.3216

Hence the compound interest on rs 10000 in 2years at 4% per annum the interest being compounded half ye

arly is Rs.824.3216

#Learn more:

Find the compound interest on Rs. 20,000 in 2 years at 4

% per annum, the interest being compounded half-yearly.

https://brainly.in/question/5115448

it may help you

Answered by george0096
3

Answer:

  • Amount is ₹ 17364.375
  • CI is ₹ 2364.375

Step-by-step explanation:

Given that:

  • Principal = ₹ 15000
  • Time = 3/2 years
  • Rate = 10%

As we know that:

If interest is compounded half-yearly:

  • Time = 2n = 2 × 3/2 = 3 half-years
  • Rate = R/2 = 10/2 = 5%

And,

\sf{Amount=Principal\bigg(1+\dfrac{Rate}{100}\bigg)^{Time}}

Where,

  • Principal = ₹ 15000
  • Rate = 5%
  • Time = 3 half-years

Substituting the values,

\sf{Amount=15000\bigg(1+\dfrac{5}{100}\bigg)^3}

Adding 1 and 5/100,

\sf{\longrightarrow15000\bigg(\dfrac{100+5}{100}\bigg)^3}

\sf{\longrightarrow15000\bigg(\dfrac{105}{100}\bigg)^3}

Reducing the numbers,

\sf{\longrightarrow15000\bigg(\dfrac{21}{20}\bigg)^3}

Opening the bracket,

\sf{\longrightarrow15000\times\dfrac{21}{20}\times\dfrac{21}{20}\times\dfrac{21}{20}}

Cutting off the zeros,

\sf{\longrightarrow15\!\!\!\not{0}\!\!\!\not{0}\!\!\!\not{0}\times\dfrac{21}{2\!\!\!\not{0}}\times\dfrac{21}{2\!\!\!\not{0}}\times\dfrac{21}{2\!\!\!\not{0}}}

\sf{\longrightarrow15\times\dfrac{21}{2}\times\dfrac{21}{2}\times\dfrac{21}{2}}

Multiplying the numbers,

\sf{\longrightarrow\dfrac{138915}{8}}

Dividing the numbers,

\sf{\longrightarrow17364.375}

Hence, amount is ₹ 17364.375

Now,

As we know that:

  • CI = Amount - Principal

Substituting the values,

CI = ₹(17364.375 - 15000)

= ₹ 2364.375

Abbreviations Used:

  • CI = Compound Interest
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