Find the amount and the compound
interest on 15,000 for 3/2years
at 10% per annum the interest
being compounded half yourly
Answers
Step-by-step explanation:
The compound interest on rs 10000 in 2years at 4% per annum the interest being compounded half yearly is Rs.824.3216
Step-by-step explanation:
Principal = Rs.10000
Time = 2 years
Rate of interest = 4%
No. of compounds per year = 2
Formula : A = P(1+\frac{r}{n})^{nt}A=P(1+
n
r
)
nt
Where A is amount
P is principal
r = rate of interest
n = no. of compounds per year
Substitute the values in the formula :
A = 10000(1+\frac{0.04}{2})^{2 \times 2}
A = 10824.3216
Interest = Amount - Principal
Interest = 10824.3216-10000
Interest = 824.3216
Hence the compound interest on rs 10000 in 2years at 4% per annum the interest being compounded half ye
arly is Rs.824.3216
#Learn more:
Find the compound interest on Rs. 20,000 in 2 years at 4
% per annum, the interest being compounded half-yearly.
https://brainly.in/question/5115448
it may help you
Answer:
- Amount is ₹ 17364.375
- CI is ₹ 2364.375
Step-by-step explanation:
Given that:
- Principal = ₹ 15000
- Time = 3/2 years
- Rate = 10%
As we know that:
If interest is compounded half-yearly:
- Time = 2n = 2 × 3/2 = 3 half-years
- Rate = R/2 = 10/2 = 5%
And,
Where,
- Principal = ₹ 15000
- Rate = 5%
- Time = 3 half-years
Substituting the values,
Adding 1 and 5/100,
Reducing the numbers,
Opening the bracket,
Cutting off the zeros,
Multiplying the numbers,
Dividing the numbers,
Hence, amount is ₹ 17364.375
Now,
As we know that:
- CI = Amount - Principal
Substituting the values,
CI = ₹(17364.375 - 15000)
= ₹ 2364.375
Abbreviations Used:
- CI = Compound Interest