Math, asked by umeshkumarpmc, 2 months ago

find the amount and the compound interest on ₹20000 for 11/2years at 10%per annum compounded half yearly would this interest be more than the interst he would if it was compouned annauly.​

Answers

Answered by namitmehta1006
0

Answer:

Principal (P) = ₹ 20,000

Time (t) = 1. ½ Years = 3/2 years

Rate (r) = 10%

Amount = P × (1 + (r/2 × 100)) n × 2

= ₹ 20,000 × (1 + (10/200) 3/2 × 2

= ₹ 20,000 × (210/200)3

= ₹ 20,000 × 21/20 × 21/20 × 21/20

= ₹ 23,152.50

C.I. Amount – Principal

= ₹ 23,152.50 - ₹20,000 = 23,152.50

Step-by-step explanation:

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Answered by mithusr081517
0

principal = Rs 20000

time = 11/2 years = 5.5years

Rate = 20%

- > simple interest = P × R × T

100

= 20000× 10× 5.5

100

= Rs 11,000

Amount = (principal - simple interest)

= Rs 20000 -11000

= Rs 9000

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