Question

Find the amount and the compound interest on ₹ 2500 for 2 years at 10/ per annum compounded annually solution

Answer 1

SOLUTION:-

Given:

⚫Principal,(P)= Rs.2500

⚫Time,(n)= 2 years

⚫Rate, (R)= 10%

So,

Amount:

$A= P(1 + \frac{R}{100} ) {}^{n} \ \\ \\ \ = > 2500(1 + \frac{10}{100} ) {}^{2} \\ \\ = > 2500( \frac{10 + 1}{10} ) {}^{2} \\ \\ = > 2500( \frac{11}{10} ) {}^{2} \\ \\ = > 2500 \times \frac{11}{10} \times \frac{11}{10} \\ \\ = > Rs.25 \times 11 \times 11 \\ \\ = > Rs.3025$

Now,

Compound Interest=Amount -Principal

=) Rs.3025 - Rs.2500

=) Rs.525

Hence,

⚫Amount=Rs.3025

⚫C.I.= Rs.525

Hope it helps ☺️

Answer 2

Answer:

Step-by-step explanation:

SOLUTION:-

Given:

⚫Principal,(P)= Rs.2500

⚫Time,(n)= 2 years

⚫Rate, (R)= 10%

So,

Amount:

Now,

Compound Interest=Amount -Principal

=) Rs.3025 - Rs.2500

=) Rs.525

Hence,

⚫Amount=Rs.3025

⚫C.I.= Rs.525

Hope it helps ☺️