Question

find the amount and the compound interest on 25000 for 3 years at 4% compound annually​

Answer 1

$\huge{\fbox{\fbox{\mathfrak{\red{Answer}}}}}$

It is given that ,

Principal = p = Rs 25000

Time = t = 3 years

Rate of interest per annum = r = 4%

Number of times interest paid (n ) = 3

Amount ( A ) = p ( 1 + r/100 )ⁿ

A = 25000 ( 1 + 4/100 )³

A = 25000 ( 1 + 1/25 )³

A = 25000 ( 26/25 )³

A = (25000×26×26×26)/( 25×25×25)

A = Rs 28121.60

Therefore ,

Compound interest = A - p

C.I = 28121.60 - 25000

C.I = Rs 3121.60

Answer 2

Step-by-step explanation:

Amount =

$p( {1 + r \div 100})^{</em></strong><strong><em>3</em></strong><strong><em>}$

Amount = 25000(1+4/100)^3

Amount = 25000(1+1/25)^3

Amount = 25000(26/25)^3

Amount = 25000x17576/15625

Amount = 28121.6

C.I = A - P

C.I = 28121.6 - 25000 = 3121.6