Question

Find the amount and the compound interest on 31,250 for 3 years at 12% p.a. compounded annually.​

Answer 1

Answer:

p=31250

TIME=3

Rate=12

SI=P*T*R/100

31,250*3*12/100

1125000/100

11250

Answer 2

Step-by-step explanation:

Sol.

Principal ( P )=₹ 31250

Rate (R)=12 % p.a.

Period (n)=3 years

$\color{darkcyan}\[ \begin{aligned} \tt \therefore \text { Amount }( A ) & \tt=\left(1+\frac{ R }{100}\right)^{n} \\ \\ & \tt=₹ 31250\left(1+\frac{12}{100}\right)^{3} \\ \\ & \tt=₹ 31250 \times\left(\frac{28}{25}\right)^{3} \\ \\ & \tt=₹ 31250 \times \frac{28}{25} \times \frac{28}{25} \times \frac{28}{25} \\ \\ & \tt=₹ 43904 \end{aligned} \]$

$\color{blue} \pmb{\[ \begin{aligned} \tt \therefore \text { Compound interest }=A-P &=\\ \\ \tt=₹ 43904-31250=₹ 12654 & \end{aligned} \]}$