Find the amount and the compound interest on ₹4,000 in 2 years, if the rate of interest for first year is 10%
Answers
Answered by
0
Answer:
amount=4800 compound intrest=800
Step-by-step explanation:
4000×2×10÷100=800
amount= intrest+principal
=4000+800=4800
Answered by
8
Answer:
- Amount = ₹ 4840
- Compound interest = ₹840
Step-by-step explanation:
Given that,
- Principal = ₹ 4,000
- Time = 2 years
- Rate of interest = 10%
Case (I),
❤ A = P(1 + R/100)^t
Where,
• A = Amount
• P = Principal
• R = Rate of interest
• t = Time
[ Putting values ]
➡ A = 4000(1 + 10/100)²
➡ A = 4000(100+10/100)²
➡ A = 4000(110/100)²
➡ A = 4000(55/50)²
➡ A = 4000 × 55/50 × 55/50
➡ A = 40 × 11 × 11
➡ A = ₹ 4840
Case (II),
❤ I = A - P
Where,
• I = Compound interest ( Suppose )
• A = Amount
• P = Principal
[ Putting values ]
➡ I = 4840 - 4000
➡ I = ₹840
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