Question

Find the amount and the compound interest on rs 10,000 for 3.5 years at 10%

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Amount=13959.64\:rupees}}$

${\bold{\therefore Compound\:Interest=3959.64\:rupees}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given :} \\ \implies Principal(p) = 10000 \: rupees \\ \\ \implies Rate(r) = 10\\ \\ \implies Time(t) = 3.5 \: years \\ \\ \underline \bold{to \: find :} \\ \implies amount = ? \\ \\ \implies compound \: interest = ?$

• According to given question :

$\bold{Using \: formula \: of \: Compound \: Interest : } \\ \implies A = p(1 + \frac{r}{100} )^{t} \\ \\ \implies A =10000(1 + \frac{10}{100} )^{ 3.5} \\ \\ \implies A= 10000 \times (\frac{11}{10} ) ^{3.5} \\ \\ \implies A= 10000 \times (1.1)^{3.5} \\ \\ \implies A= 10000 \times 1.395964 \\ \\ \bold{\implies A = 13959.64 \: ruppes} \\ \\ \bold{For \: Compound \: Interest : } \\ \implies C.I= a - p \\ \\ \implies C.I = 13959.64 - 10000 \\ \\ \bold{\implies C.I = 3959.64}$