Question

Find the amount and the compound interest on Rs 4000 in 2 years,if the rate of interest for first year is 10% and for the second year is 15%​

Answer 1

Answer:

Principal = (P) = ₹4,000

Time (t) = 2 years

Rate (R1) = 10% and rate (R2) = 15%

Amount = P (1 + (R1/100)) (1 + (R2/100))

= ₹ 4,000 (1 + (10/100)) (1 + (15/100))

= ₹ 4,000 × 11/10 × 23/20 = ₹5060

C.I. = Amount – Principal

= ₹5060 - ₹4000 = ₹1060

Answer 2

Answer:

10% of 4000 = 400

15% of 4400 = 660

Amount = 4400+ 5060= 9460

compound interest = 1060.

I hope this will help you. !