Math, asked by usmankhan26, 11 months ago

find the amount and the Compound interest on Rs 4800 for 2 years at 15/2% p.a.​

Answers

Answered by hhuz
44

Answer:

Amount = rs. 5547

Interest = rs. 747

Step-by-step explanation:

As we know,

Compounded Amount :

Method 1

P₁ ( 1 + R/100 )ⁿ  

Method 2

a₁ =(p₁ * r / 100)+ p₁ = p₂ ;

s.i₂ = (p₂ * r)

at the end of second yr = a₂ = p₂ + s.i₂

So,

Given :

Principle = rs. 4800

Time ( n ) = 2 yrs.

Rate = 15/2% or 7.5%

Solution :

       ( By method 1 )

4800 ( 1 + 7.5/100 )²   {= A.}

4800 ( 107.5 * 107.5 / (100)²

4800 ( 1075 * 1075 ) / 100³

5547000000/100³

5547

So, Amount is RS. 5547

Than Interest = A - P = 5547 - 4800 = 747 rs.

Answered by sumansinghss1973
5

Step-by-step explanation:

P=Rs.4800

T=2years

R=15/2%p.a.

:The interest for the first year is 4800×15×2/100×2=₹2880

The amount after the first year is₹4800+₹2880=₹7680

: the principal for the second year is rupees 7680

the interest for the second year is7680×15×1/2×100=₹576

the final amount is₹7680+₹576=₹8256

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