Question

Find the amount and the compound interest on Rs. 800000 for 2 years at 10% per annum compounded half- yearly.

Answer 1

Answer:

Given,

P = Rs.8,00,000

n = 2 years

R = 10%

Find,

The amount and the compound interest

Step-by-step explanation:

So,

=> the amount after 2 years is

A = P(1+R/2*100)²^n

= Rs.8,00,000 * (1+10/2*100)²*²

= Rs.8,00,000 * (1+1/20)^4

= Rs.8,00,000 * (21/20)^4

= Rs. 8,00,000 * 21/20 * 21/20 * 21/20 * 21/20

= Rs.5 * 194481

= Rs.9,72,405

So,

The compound interest is

amount - (original principal) = Rs.9,72,405 - Rs.8,00,000 = Rs.1,72,405

Answer 2

Answer:

Given,

P = Rs.8,00,000

n = 2 years

R = 10%

23 5.0

Find,

The amount and the compound interest

Step-by-step explanation:

So,

=> the amount after 2 years is

A = P(1+R/2*100)²^n

= Rs.8,00,000 (1+10/2*100)2+2

= Rs.8,00,000 (1+1/20)^4 =

= Rs.8,00,000 (21/20)^4

= Rs. 8,00,000 21/20 21/20 21/20 21/20

= Rs.5 * 194481

= Rs.9,72,405

So,

The compound interest is

amount - (original principal) = Rs.9,72,40! Rs.8,00,000 = Rs.1,72,405

Step-by-step explanation:

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