Find the amount and the compound interest on Rs2500for 2yrs at10%per annum, compound annually ?
Answers
Answer:
Given :-
Principle = rs. 2500
Time = 2 years
Rate = 10%
As we all know that
\begin{gathered}a \: = p \: (1 + \frac{r}{100} {)}^{t} \\ \\ \end{gathered}
a=p(1+
100
r
)
t
putting all above values in this equation :-
\begin{gathered}a \: = 2500 \times (1 + \frac{10}{100} {)}^{2} \\ \\ a \: = 2500 \times ( \frac{110}{100} {)}^{2} \\ \\ a \: = 2500 \times ( \frac{11}{10} {)}^{2} \\ \\ a \: = 2500 \times \frac{11}{10} \times \frac{11}{10} \\ \\ a \: = 25 \times 11 \times 11 \\ \\ a \: = 3025 \: rs\end{gathered}
a=2500×(1+
100
10
)
2
a=2500×(
100
110
)
2
a=2500×(
10
11
)
2
a=2500×
10
11
×
10
11
a=25×11×11
a=3025rs
so amount = 3025 rs.
Now,
compound interest = amount - principle
= 3025 rs. - 2500 rs.
= 525 rs answer
hope this helps you
### BE BRAINLY ###
Answer:
Present value=₹2500
Interest rate=10% per annum
Time=2 years
To find the amount we have the formula,
Amount(A)=P(1+(R/100))n
where P is present value, r is rate of interest, n is time in years.
Now substituting the values in above formula we get,
∴A=2500(1+10/100)2
⇒A=2500(11/10)2
⇒A=2500(121/100)
⇒A=25(121)
⇒A=₹3025
Now,
∴ Compound interest = A–P
=3025–2500=₹525
Step-by-step explanation:
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