find the amount and the compound interest on rupees 12,000 in 3 years at 5%; interest being compounded anually
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Answer:
CI=p(1+r/100)^n-p
p=rs.12000
n/time period= 3yrs
rate of interest=5%
12000(1+5/100)^3
12000(105/100)^3
12000(1.05)^3
12000*1.157625
12*1157.625=13,891.50(amount)
amount - principal = ci
13,891.50-12000= rs1,891.50
hope this helps you:)
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