Question

find the amount and the compound interest on rupees 12000 in 3 years at 5% interest being compounded annually
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Answer 1

Answer:

Amount is Rs 13,981.5 and compound interest is Rs 1891.5

Step-by-step explanation:

From the properties of compound interest :

$\boxed{\mathsf{ Amount=Principal\bigg( 1 + \dfrac{rate}{100} \bigg)^n}}$

where n represents the number of years.

Here,

Principal (P) = Rs 12,000.

Time (n) = 3 years

Rate = 5

Thus,

= > Amount = Rs 12,000 [ 1 + 5 / 100 ]^3

= > Amount = Rs 12,000 (1 + 0.05)^3

= > Amount = Rs 12,000 x (1.05)^3

= > Amount = Rs 12,000 x 1.157625

= > Amount = Rs 13,891.5

Therefore,

= > Compound interest = Amount - Principal = Rs 13,891.5 - Rs 12,000

= > Compound interest = Rs 1891.5

Hence, amount is Rs 13,981.5 and compound interest is Rs 1891.5

Answer 2

Answer:-

CP interest is Rs 1891.5 and Compound =Rs 13,981.5

$\boxed{\mathsf{(A=Amount)}}$

$\boxed{\mathsf{(P=Principal)}}$

$\boxed{\mathsf{(R=Rate)}}$

$\boxed{\mathsf{(SI=simple interest)}}$

$\boxed{\mathsf{( CP=Cost price )}}$

$\boxed{\mathsf{( A=P\bigg 1 + \dfrac{R}{100} \bigg}^n}$

P = Rs 12,000 3 years

R = 5

$= Rs 12,000 1 + \frac{5}{100} \sqrt{} ^3$

$= Rs 12,000 100 + \frac{5}{100} \sqrt{} 3$

$= Rs 12,000 x \frac{105}{10} \sqrt{} 3$

$=12,000 \: x \: 105 x \: 105 x \: = \frac{105}{( 100 x 100 x 100 ) }$

$= Rs 3 x \: 105 x \: 105 x \: = \frac{105}{( 10 x 25 ) } </p><p>$

= Rs 13,891.5

=CP is equal to the AP

=CP= Rs 13,891.5 - Rs 12,000

=CI= Rs 1891.5

Therfore:

A =₹ 13,981.5 and SI is Rs 1891.5

$\huge\red{Hope-it-Helps!!!}$