Question

find the amount and the compound interest on rupees 18000 for 2 and half years at 10% per annum compounded annually ...
....... plz answer fast.....​

Answer 1

Answer:

₹4869.

Brainliest?

Step-by-step explanation:

P=₹18000, T= 2.5 years, R=10%pa

A= P(1+R/100)^n ×(1+R/200)^2n

=18000(1+10/100)^2×(1+10/200)^2×1/2

= 18000(11/10)^2 ×(21/20)

= 18000 × 121/ 100 ×21/20

= 9×121×21

=22869

Therefore CI=A-P

= 22869-18000

₹4869.