find the amount and the compound interest on rupees 18000 for 2 and half years at 10% per annum compounded annually ...
....... plz answer fast.....
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Answer:
₹4869.
Brainliest?
Step-by-step explanation:
P=₹18000, T= 2.5 years, R=10%pa
A= P(1+R/100)^n ×(1+R/200)^2n
=18000(1+10/100)^2×(1+10/200)^2×1/2
= 18000(11/10)^2 ×(21/20)
= 18000 × 121/ 100 ×21/20
= 9×121×21
=22869
Therefore CI=A-P
= 22869-18000
₹4869.
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