find the amount and the compound interest on rupees 20000 for one 1 by 2 years at the rate of 8% per annum compounded half yearly .
Answers
Answer:
Here
P=
20,000
Rs.,
n=
3
years,
R=
8
Amount (A)=
P
(1+
100
R
)
n
=
20000
(1+
100
8
)
3
=
20000
(
25
27
)
3
=
25×25×25
20000×(27)
3
=
25
32×(27)
3
=
25,194.24
Rs.
Compound interest
(C.I)=
A−
P=
25,194.24−
20,000=
5,194.24
Hence, the compound interest is Rs. 5,
Answer:
Here
P=
20,000
Rs.,
n=
3
years,
R=
8
Amount (A)=
P
(1+
100
R
)
n
=
20000
(1+
100
8
)
3
=
20000
(
25
27
)
3
=
25×25×25
20000×(27)
3
=
25
32×(27)
3
=
25,194.24
Rs.
Compound interest
(C.I)=
A−
P=
25,194.24−
20,000=
5,194.24
Hence, the compound interest is Rs. 5,
According to the question
d t
d V
= K×(surface area)
V=
3
4
πr
3
,SA= 4πr
2
dt
d (
3
4
πr
3
)
= K× 4πr
2
3
4π
dt
dr
3
= 4πKr
2
3
4π
× 3r
2
×
dt
dr
= 4πKr
2
dt
dr
= K
Hence true.