find the amount and the compound interest on rupees 2500 for 2 years at 10% per annum compounded annually
Answers
Answered by
93
A=p(1+r/100)to the power n
2500(1+10/100)2
2500(110/100)2
2500*(11/10)2
2500*11/10*11/10
3025 =amount
Answered by
80
Given .
Principal amount = P=2500
Duration/Time = n = 2 years
Rate of Interest Per annum= i = 10%
Required to find is A = compound Interest
we know That..
For compound Interest...
A=P(1+i)^n-P
substituting above information..
A = 2500(1+10/100)^2 -2500
A= 2500(1+0.1)^2 - 2500
A= 2500(1.1)^2 - 2500
A = 2500(1.21) - 2500
A= 3025 - 2500
A= 525
so the compound Interest= 525
compounded amount = Principal amount + compound interest
= 2500+525 = 3025
Principal amount = P=2500
Duration/Time = n = 2 years
Rate of Interest Per annum= i = 10%
Required to find is A = compound Interest
we know That..
For compound Interest...
A=P(1+i)^n-P
substituting above information..
A = 2500(1+10/100)^2 -2500
A= 2500(1+0.1)^2 - 2500
A= 2500(1.1)^2 - 2500
A = 2500(1.21) - 2500
A= 3025 - 2500
A= 525
so the compound Interest= 525
compounded amount = Principal amount + compound interest
= 2500+525 = 3025
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