Question

Find the amount and the compound interest on rupees 64000 for 1 1/2 years at 15% per annum, compunded half-yerly

Answer 1

Answer:

Amount is 79507 and Compound Interest is 15507

Explanation:

Given :

• Principal (p) => 64000
• Time (t) => 1 1/2=3/2 =3/2*2=3
• Rate (r) => 15% = 15/2

To Find :

• Amount(A) and Compound Interest(CI)

Solution :

$\sf{A}=p\bigg(1+\dfrac{r}{100}\bigg)^{n}$

$\sf{A}= 64000\bigg(1+\dfrac{15}{2\times100}\bigg)^{3}$

$\sf{A}= 64000\bigg(\dfrac{43}{40}\bigg)^{3}$

$\sf{A}= 64000\times \dfrac{79507}{64000}$

$\because \sf{Amount} =79507$

$\sf{CI=Amount-Principle}$

$\sf{CI} =79507 -64000$

$\because \sf{Compound\ Interest} = 15507$

Answer 2

$\mathfrak{\huge{\underline{\underline{\red{Question\:?}}}}}$

✴ Find the amount and the compound interest on rupees 64000 for 1 1/2 years at 15% per annum, compunded half-yerly.

$\mathcal{\huge{\fbox{\green{AnSwEr:-}}}}$

✒ Amount is ₹ 79507 and Compound Interest is ₹ 15507.

$\mathcal{\huge{\fbox{\purple{Solution:-}}}}$

⚚ Given :-

• Principal (p) => 64000

• Time (t) => 1 (1/2) = 3/2 =3/2 × 2 = 3

• Rate (r) => 15% = 15/2

♜ To Find :-

• The amount

• The compound interest

♞ Calculation :-

✵ $\sf{A}=p\bigg(1+\dfrac{r}{100}\bigg)^{n}$

➠ A = 64000 ( 1 + 15 /2 × 100 )³

➠ A = 64000 (43/40)³

➠ $\sf{A}= 64000\times \dfrac{79507}{64000}$

➠ $\because \sf{Amount}$ =79507

➭ Hence, Amount is ₹ 79507.

✵ $\sf{CI=Amount-Principle}$

➠$\sf{CI}$ =79507 -64000

➠$\because \sf{Compound\ Interest}$ = 15507

➭ Hence, Compound Interest is ₹ 15507.

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