Question

Find the amount and the compound interest on rupees 8000 for 2 years at 6% per annum, compounded
annually​

Answer 1

I can't see your question

Answer 2

Answer:

here  \\ \: p = 8000  \\ \: n = 2 \\ r = 6 \\ amount \:  =  p \times {(1 +  \frac{r}{100} )}^{n}  \\  =  > amount = 8000 \times  {(1 +  \frac{6}{100} )}^{2}  \\  =  > amount = 8000 \times  {( \frac{106}{100} )}^{2}  \\  =  > amount = 8000 \times  \frac{106}{100}  \times  \frac{106}{100}  \\  =  > amount \:  = 8000 \times  \frac{11236}{10000}  \\  =  > amount = 8 \times  \frac{11236}{10}  =  \frac{89888}{10}  = 8988.8 \\ compoun \: interest = amount - principal \\  =  > compound \: interest = 8988.8 - 8000 = 988.8

So , Amount paid at the end of 2nd year = Rs. 8988.80

and Compound interest = Rs.988.8