Question

find the amount and the compound interest on8000 at 5% per annum for 2years​

Answer 1

Answer:

A=8820

C.I=820

Step-by-step explanation:

A= P(1+ r/100)^T

P=8000

R=5%

T=2 years p.a.

A=8000 (1+5/100)^2

=8000 (105/100)^2

=8000 (21/20)^2

=8000×21/20×21/20

=20×21×21

=8820

therefore, C.I =A-P

C.I = 8820-8000

= 820

# hope this will help you

# please mark as brainliest

# follow me

Answer 2

Answer:

$\small{ \underline{ \bf \purple{amount = \: rs . 8820}}}$

CI = 820/-

step by step explanation:

Amount = Principle ×( 1+ R upon 100)^

time.

A= 8000×( 1+ 5 upon 100)^2

A= 8000(105 upon 100)^2

A= 8000( 21/20 × 21/20)

A= 8000× 21/20×21/20

A= 20×21×21. ( as we divide 20 by

8000 we get 400 and

again divided by 20 we

20)

A= 8820/-

CI = Amount- Principle

CI = 8820-8000

CI = 820/-

# mark it as the BRAINLIEST

# follow me

# thank my 10 answers and get a surprise for sure!!!!!