Question

Find the amount and the compound intrest on2000 at 10% p.a for 2 and half yrs compound annuvally. Plzz dont spam​

Answer 1

Answer:

Amount = Rs 2541

Compound Interest = Rs 541

Step-by-step explanation:

${\underline{{\text{Given}}}}$

Principal (P) = Rs 2000

Rate of interest (r) = 10 %

$\text{Time (t)} = 2 \dfrac{1}{2} yr$

${\underline{{\text{To Find:}}}}$

Amount (A)

Compound Interest (C.I)

${\underline{{\text{Solution:}}}}$

As, We See time is given in fraction So, We have to solve it in different step.

• 1st for 2 yr

• 2nd for 1/2 yr

1st Solution:

P = Rs 2000

r = 10 %

t = 2 yr

Formula for Amount in Compound Interest

$\boxed{{A = P(1 + \dfrac{r}{100})^{t}}}$

$2000(1 + \frac{10}{100} ) {}^{2} \\ \\ =2000( \frac{110}{100} ) {}^{2} \\ \\= 2000 { (\frac{11}{10} )}^{2} \\ \\ =2000 \times \frac{121}{100} \\ \\= 20 \times 121 \\ \\= 2420$

2nd Solution:

P = 2420 Rs

r = 10 %

t = 1/2 yr

Formula for Amount in Simple Interest

$\boxed{{A = \dfrac{Prt}{100}){}}}$

$\frac{2420 \times 1 \times 10}{100 \times 2} \\ \\ = \frac{ \cancel{2420} \times \cancel{10}}{ \cancel{2 \times 100}} \\ \\ =121$

Now,

Amount = Rs (2420 + 121)

= Rs 2541

Compound Interest = Rs ( 2541 - 2000)

= Rs 541

Answer 2

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