find the amount at the end of 2 years on rupees 4000 at 4% p a compound annually
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Answer : 4326.4 rs
Step-by-step explanation:
P= 4000 rs
R=4%pa
t =2 years
A = p[1+r/100]^n
A=4000×[1+4/100]^2
A= 4000 × (26/25)^2
A =4000× 26/25 × 26/25
A= 160. × 26 × 26/25
A = 32×26×26 /5
A= 21632/5
A= 4326.4 rs
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