Find the amount at the end of two years on Rs.1000 at 4% p.a. compounded annualy.
Answers
Answered by
1
A=P (1+r/100)^n
put values
1000×1+4/100^2
then solve it
put values
1000×1+4/100^2
then solve it
Answered by
2
Answer:
Step-by-step explanation:
A = p(1 + r/100)^n
A = 1000(1 + 4/100)^2
A = 1000(1 + 1/25)^2
A = 1000(26/25)^2
A = 1000 × 676/625
A = 1081.1
Ananyajain12:
But on my books answer sheet answer is 1081.60
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