Question

find the amount if p=8000r=10% time =5yrs​

Answer 1

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$Given\:,$

Principle amount (P) = 8000

Rate of Interest (R)= 10%

Time (T) = 5 years

Amount = ?

$\therefore$ S.I. = $\frac{P\:×\:T\:×\:R}{100}$

$\implies$ S.I. = $\frac{8000\:×\:5\:×\:10}{100}$

$\implies$ S.I. = $\frac{8000\:×\:5}{10}$

$\implies$ S.I. = $\frac{8000}{2}$

$\implies$ S.I. = 4000

$\therefore$ Amount = P + S.I

$\implies$ Amount = 8000 + 4000

$\implies$ Amount = 12000

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$MARK \:HER \:BRAINLIEST\: ☟︎︎︎$

Answer 2

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*Question:

Find the amount if p=8000r=10% time =5yrs.

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Answer:

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It is simple.

Step-by-step explanation:

$principal \: = \:rs \: 8000 \\rate \: = \: 10\% \: per \: annum \\ time \: = \: 5 \: years$

Simply we have to use the formula .

$simple \: interest \: = \: \frac{p \times r \times t}{100} \\ \\ = \: \frac{8000 \times 10 \times 5 }{100}$

$= 80 \times 10 \times 5 \\ = 800 \times 5 \: \: \: \: \: \: \: \: \\ = 4000 \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Rs 4000 .

If you want to find amount also then,

Use this Formula for finding the amount.

$amount \\ = principal \: + \: simple \: interest.$

$= \: rs(8000 \: + \: 4000) \\ = rs12000 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

So the amount is Rs 12,000

and Simple interest is Rs 4,000

Hope you like it dear.

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