Question

Find the amount if Rs. 10,000 is invested at 10% p.a. for 2 years when compounded annually?

Answer 1

Answer:

12100

Step-by-step explanation:

Principle (P) = 10,000

Rate (R) = 10% i.e. 0.1%

Time (N) = 2 yrs

CI = P[(1 + i)^n]CI=P[(1+i)

n

]

CI = 10,000[(1 + 0.1)^2]CI=10,000[(1+0.1)

2

]

[(1.1)^2] = 1.21[(1.1)

2

]=1.21

CI = 10,000 × 1.21 = 12,100

mark me brainliest

Answer 2

Answer:

Step-by-step explanation:

We know that  $Amt = p(1+i)^n$

From the given data p = 10,000

Rate of interest = 10%

Time = 2 yrs

Substituting the input values we have the equation as under

$Amt = p(1+i)^n$

$Amt = 10,000(1+0.1)^2$

$Amt = 10,000(1.1)^2$

$Amt = 10,000 (1.21)$

$Amt = 12,100$

Hence the amount is ₹ 12,100